164=x+(3+2x)+4x

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Solution for 164=x+(3+2x)+4x equation: 



164=x+(3+2x)+4x

We move all terms to the left:

164-(x+(3+2x)+4x)=0

We add all the numbers together, and all the variables

-(x+(2x+3)+4x)+164=0



We calculate terms in parentheses: -(x+(2x+3)+4x), so:

x+(2x+3)+4x

We add all the numbers together, and all the variables

5x+(2x+3)

We get rid of parentheses

5x+2x+3

We add all the numbers together, and all the variables

7x+3

Back to the equation:

-(7x+3)



We get rid of parentheses

-7x-3+164=0

We add all the numbers together, and all the variables

-7x+161=0

We move all terms containing x to the left, all other terms to the right

-7x=-161

x=-161/-7

x=+23

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