16560=12x2+4x-8

Solution for 16560=12x2+4x-8 equation:

16560=12x^2+4x-8

We move all terms to the left:

16560-(12x^2+4x-8)=0

We get rid of parentheses

-12x^2-4x+8+16560=0

We add all the numbers together, and all the variables

-12x^2-4x+16568=0

a = -12; b = -4; c = +16568;
Δ = b2-4ac
Δ = -42-4·(-12)·16568
Δ = 795280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{795280}=\sqrt{16*49705}=\sqrt{16}*\sqrt{49705}=4\sqrt{49705}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{49705}}{2*-12}=\frac{4-4\sqrt{49705}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{49705}}{2*-12}=\frac{4+4\sqrt{49705}}{-24}
$