168=1/2(12)(16+b2)

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Solution for 168=1/2(12)(16+b2) equation: 



168=1/2(12)(16+b2)

We move all terms to the left:

168-(1/2(12)(16+b2))=0



Domain of the equation: 212(16+b2))!=0

b∈R



We add all the numbers together, and all the variables

-(1/212(+b^2+16))+168=0

We multiply all the terms by the denominator


-(1+168*212(+b^2+16))=0



We calculate terms in parentheses: -(1+168*212(+b^2+16)), so:

1+168*212(+b^2+16)

determiningTheFunctionDomain
168*212(+b^2+16)+1

Wy multiply elements

35616b(++1

We use the square of the difference formula

35616b(+1

Back to the equation:

-(35616b(+1)



We add all the numbers together, and all the variables

-(35616b1=0

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