168=4x+(1/3x*2)

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Solution for 168=4x+(1/3x*2) equation: 



168=4x+(1/3x*2)

We move all terms to the left:

168-(4x+(1/3x*2))=0



Domain of the equation: 3x*2))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(4x+(+1/3x*2))+168=0

We multiply all the terms by the denominator


-(4x+(+1+168*3x*2))=0



We calculate terms in parentheses: -(4x+(+1+168*3x*2)), so:

4x+(+1+168*3x*2)

We add all the numbers together, and all the variables

4x+(168*3x*2+1)

We get rid of parentheses

4x+168*3x*2+1

Wy multiply elements

4x+1008x*2+1

Wy multiply elements

4x+2016x+1

We add all the numbers together, and all the variables

2020x+1

Back to the equation:

-(2020x+1)



We get rid of parentheses

-2020x-1=0

We move all terms containing x to the left, all other terms to the right

-2020x=1

x=1/-2020

x=-1/2020

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