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169=a2
We move all terms to the left:
169-(a2)=0
We add all the numbers together, and all the variables
-1a^2+169=0
a = -1; b = 0; c = +169;
Δ = b2-4ac
Δ = 02-4·(-1)·169
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-26}{2*-1}=\frac{-26}{-2} =+13 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+26}{2*-1}=\frac{26}{-2} =-13 $
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