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169x^2-109x-36=0
a = 169; b = -109; c = -36;
Δ = b2-4ac
Δ = -1092-4·169·(-36)
Δ = 36217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-109)-\sqrt{36217}}{2*169}=\frac{109-\sqrt{36217}}{338} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-109)+\sqrt{36217}}{2*169}=\frac{109+\sqrt{36217}}{338} $
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