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169x^2-196=0
a = 169; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·169·(-196)
Δ = 132496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{132496}=364$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-364}{2*169}=\frac{-364}{338} =-1+1/13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+364}{2*169}=\frac{364}{338} =1+1/13 $
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