16=(1/2)(23+x)

Solution for 16=(1/2)(23+x) equation:

16=(1/2)(23+x)

We move all terms to the left:

16-((1/2)(23+x))=0


Domain of the equation: 2)(23+x))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/2)(x+23))+16=0

We multiply parentheses ..

-((+x^2+1/2*23))+16=0

We multiply all the terms by the denominator


-((+x^2+1+16*2*23))=0


We calculate terms in parentheses: -((+x^2+1+16*2*23)), so:

(+x^2+1+16*2*23)

We get rid of parentheses

x^2+1+16*2*23

We add all the numbers together, and all the variables

x^2+737

Back to the equation:

-(x^2+737)


We get rid of parentheses

-x^2-737=0

We add all the numbers together, and all the variables

-1x^2-737=0

a = -1; b = 0; c = -737;
Δ = b2-4ac
Δ = 02-4·(-1)·(-737)
Δ = -2948
Delta is less than zero, so there is no solution for the equation