16=(3x-2)(x)

Solution for 16=(3x-2)(x) equation:

16=(3x-2)(x)

We move all terms to the left:

16-((3x-2)(x))=0


We calculate terms in parentheses: -((3x-2)x), so:

(3x-2)x

We multiply parentheses

3x^2-2x

Back to the equation:

-(3x^2-2x)


We get rid of parentheses

-3x^2+2x+16=0

a = -3; b = 2; c = +16;
Δ = b2-4ac
Δ = 22-4·(-3)·16
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-14}{2*-3}=\frac{-16}{-6}
=2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+14}{2*-3}=\frac{12}{-6}
=-2
$