16=(3x-7)+(3x-1)

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Solution for 16=(3x-7)+(3x-1) equation: 



16=(3x-7)+(3x-1)

We move all terms to the left:

16-((3x-7)+(3x-1))=0



We calculate terms in parentheses: -((3x-7)+(3x-1)), so:

(3x-7)+(3x-1)

We get rid of parentheses

3x+3x-7-1

We add all the numbers together, and all the variables

6x-8

Back to the equation:

-(6x-8)



We get rid of parentheses

-6x+8+16=0

We add all the numbers together, and all the variables

-6x+24=0

We move all terms containing x to the left, all other terms to the right

-6x=-24

x=-24/-6

x=+4

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