16=(x+3)(x-3)

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Solution for 16=(x+3)(x-3) equation: 



16=(x+3)(x-3)

We move all terms to the left:

16-((x+3)(x-3))=0

We use the square of the difference formula

x^2+9+16=0

We add all the numbers together, and all the variables

x^2+25=0

a = 1; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·1·25
Δ = -100
Delta is less than zero, so there is no solution for the equation

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