16=-2(1-x)+3(x+1)

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Solution for 16=-2(1-x)+3(x+1) equation: 



16=-2(1-x)+3(x+1)

We move all terms to the left:

16-(-2(1-x)+3(x+1))=0

We add all the numbers together, and all the variables

-(-2(-1x+1)+3(x+1))+16=0



We calculate terms in parentheses: -(-2(-1x+1)+3(x+1)), so:

-2(-1x+1)+3(x+1)

We multiply parentheses

2x+3x-2+3

We add all the numbers together, and all the variables

5x+1

Back to the equation:

-(5x+1)



We get rid of parentheses

-5x-1+16=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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