16=-3(7x-4)+3x

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Solution for 16=-3(7x-4)+3x equation: 



16=-3(7x-4)+3x

We move all terms to the left:

16-(-3(7x-4)+3x)=0



We calculate terms in parentheses: -(-3(7x-4)+3x), so:

-3(7x-4)+3x

We add all the numbers together, and all the variables

3x-3(7x-4)

We multiply parentheses

3x-21x+12

We add all the numbers together, and all the variables

-18x+12

Back to the equation:

-(-18x+12)



We get rid of parentheses

18x-12+16=0

We add all the numbers together, and all the variables

18x+4=0

We move all terms containing x to the left, all other terms to the right

18x=-4

x=-4/18

x=-2/9

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