16=1/2(4)(3+b)

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Solution for 16=1/2(4)(3+b) equation: 



16=1/2(4)(3+b)

We move all terms to the left:

16-(1/2(4)(3+b))=0



Domain of the equation: 24(3+b))!=0

b∈R



We add all the numbers together, and all the variables

-(1/24(b+3))+16=0

We multiply all the terms by the denominator


-(1+16*24(b+3))=0



We calculate terms in parentheses: -(1+16*24(b+3)), so:

1+16*24(b+3)

determiningTheFunctionDomain
16*24(b+3)+1

Wy multiply elements

384b(b+1

Back to the equation:

-(384b(b+1)





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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384b(b+1





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