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16=1/24(3+b2)
We move all terms to the left:
16-(1/24(3+b2))=0
Domain of the equation: 24(3+b2))!=0We add all the numbers together, and all the variables
b∈R
-(1/24(+b^2+3))+16=0
We multiply all the terms by the denominator
-(1+16*24(+b^2+3))=0
We calculate terms in parentheses: -(1+16*24(+b^2+3)), so:We add all the numbers together, and all the variables
1+16*24(+b^2+3)
determiningTheFunctionDomain 16*24(+b^2+3)+1
Wy multiply elements
384b(++1
We use the square of the difference formula
384b(+1
Back to the equation:
-(384b(+1)
-(384b1=0
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