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16=1/5b-8
We move all terms to the left:
16-(1/5b-8)=0
Domain of the equation: 5b-8)!=0We get rid of parentheses
b∈R
-1/5b+8+16=0
We multiply all the terms by the denominator
8*5b+16*5b-1=0
Wy multiply elements
40b+80b-1=0
We add all the numbers together, and all the variables
120b-1=0
We move all terms containing b to the left, all other terms to the right
120b=1
b=1/120
b=1/120
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