16=120+3b

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Solution for 16=120+3b equation: 



16=120+3b

We move all terms to the left:

16-(120+3b)=0

We add all the numbers together, and all the variables

-(3b+120)+16=0

We get rid of parentheses

-3b-120+16=0

We add all the numbers together, and all the variables

-3b-104=0

We move all terms containing b to the left, all other terms to the right

-3b=104

b=104/-3

b=-34+2/3

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