16=2(-8c+3)+10

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Solution for 16=2(-8c+3)+10 equation: 



16=2(-8c+3)+10

We move all terms to the left:

16-(2(-8c+3)+10)=0



We calculate terms in parentheses: -(2(-8c+3)+10), so:

2(-8c+3)+10

We multiply parentheses

-16c+6+10

We add all the numbers together, and all the variables

-16c+16

Back to the equation:

-(-16c+16)



We get rid of parentheses

16c-16+16=0

We add all the numbers together, and all the variables

16c=0

c=0/16

c=0

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