16=2(2x+x-2)

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Solution for 16=2(2x+x-2) equation:



16=2(2x+x-2)
We move all terms to the left:
16-(2(2x+x-2))=0
We add all the numbers together, and all the variables
-(2(3x-2))+16=0
We calculate terms in parentheses: -(2(3x-2)), so:
2(3x-2)
We multiply parentheses
6x-4
Back to the equation:
-(6x-4)
We get rid of parentheses
-6x+4+16=0
We add all the numbers together, and all the variables
-6x+20=0
We move all terms containing x to the left, all other terms to the right
-6x=-20
x=-20/-6
x=3+1/3

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