16=2(3+b)

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Solution for 16=2(3+b) equation: 



16=2(3+b)

We move all terms to the left:

16-(2(3+b))=0

We add all the numbers together, and all the variables

-(2(b+3))+16=0



We calculate terms in parentheses: -(2(b+3)), so:

2(b+3)

We multiply parentheses

2b+6

Back to the equation:

-(2b+6)



We get rid of parentheses

-2b-6+16=0

We add all the numbers together, and all the variables

-2b+10=0

We move all terms containing b to the left, all other terms to the right

-2b=-10

b=-10/-2

b=+5

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