16=2(3x-6)+x

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Solution for 16=2(3x-6)+x equation: 



16=2(3x-6)+x

We move all terms to the left:

16-(2(3x-6)+x)=0



We calculate terms in parentheses: -(2(3x-6)+x), so:

2(3x-6)+x

We add all the numbers together, and all the variables

x+2(3x-6)

We multiply parentheses

x+6x-12

We add all the numbers together, and all the variables

7x-12

Back to the equation:

-(7x-12)



We get rid of parentheses

-7x+12+16=0

We add all the numbers together, and all the variables

-7x+28=0

We move all terms containing x to the left, all other terms to the right

-7x=-28

x=-28/-7

x=+4

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