16=2(u+3)-4u

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Solution for 16=2(u+3)-4u equation: 



16=2(u+3)-4u

We move all terms to the left:

16-(2(u+3)-4u)=0



We calculate terms in parentheses: -(2(u+3)-4u), so:

2(u+3)-4u

We add all the numbers together, and all the variables

-4u+2(u+3)

We multiply parentheses

-4u+2u+6

We add all the numbers together, and all the variables

-2u+6

Back to the equation:

-(-2u+6)



We get rid of parentheses

2u-6+16=0

We add all the numbers together, and all the variables

2u+10=0

We move all terms containing u to the left, all other terms to the right

2u=-10

u=-10/2

u=-5

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