16=2(x+3)-7x

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Solution for 16=2(x+3)-7x equation: 



16=2(x+3)-7x

We move all terms to the left:

16-(2(x+3)-7x)=0



We calculate terms in parentheses: -(2(x+3)-7x), so:

2(x+3)-7x

We add all the numbers together, and all the variables

-7x+2(x+3)

We multiply parentheses

-7x+2x+6

We add all the numbers together, and all the variables

-5x+6

Back to the equation:

-(-5x+6)



We get rid of parentheses

5x-6+16=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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