16=24k2+8k

Solution for 16=24k2+8k equation:

16=24k^2+8k

We move all terms to the left:

16-(24k^2+8k)=0

We get rid of parentheses

-24k^2-8k+16=0

a = -24; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·(-24)·16
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-40}{2*-24}=\frac{-32}{-48}
=2/3
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+40}{2*-24}=\frac{48}{-48}
=-1
$