16=2x+3(4+x)

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Solution for 16=2x+3(4+x) equation: 



16=2x+3(4+x)

We move all terms to the left:

16-(2x+3(4+x))=0

We add all the numbers together, and all the variables

-(2x+3(x+4))+16=0



We calculate terms in parentheses: -(2x+3(x+4)), so:

2x+3(x+4)

We multiply parentheses

2x+3x+12

We add all the numbers together, and all the variables

5x+12

Back to the equation:

-(5x+12)



We get rid of parentheses

-5x-12+16=0

We add all the numbers together, and all the variables

-5x+4=0

We move all terms containing x to the left, all other terms to the right

-5x=-4

x=-4/-5

x=4/5

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