16=4(b-3)+7(4+4b)

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Solution for 16=4(b-3)+7(4+4b) equation: 


Simplifying
16 = 4(b + -3) + 7(4 + 4b)

Reorder the terms:
16 = 4(-3 + b) + 7(4 + 4b)
16 = (-3 * 4 + b * 4) + 7(4 + 4b)
16 = (-12 + 4b) + 7(4 + 4b)
16 = -12 + 4b + (4 * 7 + 4b * 7)
16 = -12 + 4b + (28 + 28b)

Reorder the terms:
16 = -12 + 28 + 4b + 28b

Combine like terms: -12 + 28 = 16
16 = 16 + 4b + 28b

Combine like terms: 4b + 28b = 32b
16 = 16 + 32b

Add '-16' to each side of the equation.
16 + -16 = 16 + -16 + 32b

Combine like terms: 16 + -16 = 0
0 = 16 + -16 + 32b

Combine like terms: 16 + -16 = 0
0 = 0 + 32b
0 = 32b

Solving
0 = 32b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-32b' to each side of the equation.
0 + -32b = 32b + -32b
Remove the zero:
-32b = 32b + -32b

Combine like terms: 32b + -32b = 0
-32b = 0

Divide each side by '-32'.
b = 0

Simplifying
b = 0

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