16=4+(n+3)

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Solution for 16=4+(n+3) equation: 



16=4+(n+3)

We move all terms to the left:

16-(4+(n+3))=0



We calculate terms in parentheses: -(4+(n+3)), so:

4+(n+3)

determiningTheFunctionDomain
(n+3)+4

We get rid of parentheses

n+3+4

We add all the numbers together, and all the variables

n+7

Back to the equation:

-(n+7)



We get rid of parentheses

-n-7+16=0

We add all the numbers together, and all the variables

-1n+9=0

We move all terms containing n to the left, all other terms to the right

-n=-9

n=-9/-1

n=+9

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