16=4+3(t-1)

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Solution for 16=4+3(t-1) equation: 



16=4+3(t-1)

We move all terms to the left:

16-(4+3(t-1))=0



We calculate terms in parentheses: -(4+3(t-1)), so:

4+3(t-1)

determiningTheFunctionDomain
3(t-1)+4

We multiply parentheses

3t-3+4

We add all the numbers together, and all the variables

3t+1

Back to the equation:

-(3t+1)



We get rid of parentheses

-3t-1+16=0

We add all the numbers together, and all the variables

-3t+15=0

We move all terms containing t to the left, all other terms to the right

-3t=-15

t=-15/-3

t=+5

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