16=4+3(t-2)

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Solution for 16=4+3(t-2) equation: 



16=4+3(t-2)

We move all terms to the left:

16-(4+3(t-2))=0



We calculate terms in parentheses: -(4+3(t-2)), so:

4+3(t-2)

determiningTheFunctionDomain
3(t-2)+4

We multiply parentheses

3t-6+4

We add all the numbers together, and all the variables

3t-2

Back to the equation:

-(3t-2)



We get rid of parentheses

-3t+2+16=0

We add all the numbers together, and all the variables

-3t+18=0

We move all terms containing t to the left, all other terms to the right

-3t=-18

t=-18/-3

t=+6

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