16=4x*4x+4x

Solution for 16=4x*4x+4x equation:

16=4x*4x+4x

We move all terms to the left:

16-(4x*4x+4x)=0

We add all the numbers together, and all the variables

-(+4x+4x*4x)+16=0

We get rid of parentheses

-4x-4x*4x+16=0

Wy multiply elements

-16x^2-4x+16=0

a = -16; b = -4; c = +16;
Δ = b2-4ac
Δ = -42-4·(-16)·16
Δ = 1040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1040}=\sqrt{16*65}=\sqrt{16}*\sqrt{65}=4\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{65}}{2*-16}=\frac{4-4\sqrt{65}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{65}}{2*-16}=\frac{4+4\sqrt{65}}{-32}
$