16=5(u+2)-3u

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Solution for 16=5(u+2)-3u equation: 



16=5(u+2)-3u

We move all terms to the left:

16-(5(u+2)-3u)=0



We calculate terms in parentheses: -(5(u+2)-3u), so:

5(u+2)-3u

We add all the numbers together, and all the variables

-3u+5(u+2)

We multiply parentheses

-3u+5u+10

We add all the numbers together, and all the variables

2u+10

Back to the equation:

-(2u+10)



We get rid of parentheses

-2u-10+16=0

We add all the numbers together, and all the variables

-2u+6=0

We move all terms containing u to the left, all other terms to the right

-2u=-6

u=-6/-2

u=+3

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