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16=6(x-5)4x
We move all terms to the left:
16-(6(x-5)4x)=0
We calculate terms in parentheses: -(6(x-5)4x), so:We get rid of parentheses
6(x-5)4x
We multiply parentheses
24x^2-120x
Back to the equation:
-(24x^2-120x)
-24x^2+120x+16=0
a = -24; b = 120; c = +16;
Δ = b2-4ac
Δ = 1202-4·(-24)·16
Δ = 15936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15936}=\sqrt{64*249}=\sqrt{64}*\sqrt{249}=8\sqrt{249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-8\sqrt{249}}{2*-24}=\frac{-120-8\sqrt{249}}{-48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+8\sqrt{249}}{2*-24}=\frac{-120+8\sqrt{249}}{-48} $
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