16=7(3x-2)-6(3x-2)

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Solution for 16=7(3x-2)-6(3x-2) equation: 



16=7(3x-2)-6(3x-2)

We move all terms to the left:

16-(7(3x-2)-6(3x-2))=0



We calculate terms in parentheses: -(7(3x-2)-6(3x-2)), so:

7(3x-2)-6(3x-2)

We multiply parentheses

21x-18x-14+12

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We get rid of parentheses

-3x+2+16=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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