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16=x(2x+14)
We move all terms to the left:
16-(x(2x+14))=0
We calculate terms in parentheses: -(x(2x+14)), so:We get rid of parentheses
x(2x+14)
We multiply parentheses
2x^2+14x
Back to the equation:
-(2x^2+14x)
-2x^2-14x+16=0
a = -2; b = -14; c = +16;
Δ = b2-4ac
Δ = -142-4·(-2)·16
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-18}{2*-2}=\frac{-4}{-4} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+18}{2*-2}=\frac{32}{-4} =-8 $
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