16=x+(2x+1)

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Solution for 16=x+(2x+1) equation: 



16=x+(2x+1)

We move all terms to the left:

16-(x+(2x+1))=0



We calculate terms in parentheses: -(x+(2x+1)), so:

x+(2x+1)

We get rid of parentheses

x+2x+1

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We get rid of parentheses

-3x-1+16=0

We add all the numbers together, and all the variables

-3x+15=0

We move all terms containing x to the left, all other terms to the right

-3x=-15

x=-15/-3

x=+5

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