16a-8(3a+4)=-4(a-5)+12(3a-9)

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Solution for 16a-8(3a+4)=-4(a-5)+12(3a-9) equation: 



16a-8(3a+4)=-4(a-5)+12(3a-9)

We move all terms to the left:

16a-8(3a+4)-(-4(a-5)+12(3a-9))=0

We multiply parentheses

16a-24a-(-4(a-5)+12(3a-9))-32=0



We calculate terms in parentheses: -(-4(a-5)+12(3a-9)), so:

-4(a-5)+12(3a-9)

We multiply parentheses

-4a+36a+20-108

We add all the numbers together, and all the variables

32a-88

Back to the equation:

-(32a-88)



We add all the numbers together, and all the variables

-8a-(32a-88)-32=0

We get rid of parentheses

-8a-32a+88-32=0

We add all the numbers together, and all the variables

-40a+56=0

We move all terms containing a to the left, all other terms to the right

-40a=-56

a=-56/-40

a=1+2/5

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