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16a^2-14a=a2-3a
We move all terms to the left:
16a^2-14a-(a2-3a)=0
We add all the numbers together, and all the variables
16a^2-(+a^2-3a)-14a=0
We get rid of parentheses
16a^2-a^2+3a-14a=0
We add all the numbers together, and all the variables
15a^2-11a=0
a = 15; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·15·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*15}=\frac{0}{30} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*15}=\frac{22}{30} =11/15 $
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