16b+40=4(5b-1)

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Solution for 16b+40=4(5b-1) equation: 



16b+40=4(5b-1)

We move all terms to the left:

16b+40-(4(5b-1))=0



We calculate terms in parentheses: -(4(5b-1)), so:

4(5b-1)

We multiply parentheses

20b-4

Back to the equation:

-(20b-4)



We get rid of parentheses

16b-20b+4+40=0

We add all the numbers together, and all the variables

-4b+44=0

We move all terms containing b to the left, all other terms to the right

-4b=-44

b=-44/-4

b=+11

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