16b2-8b2+24b2-40b2=0

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Solution for 16b2-8b2+24b2-40b2=0 equation: 



16b^2-8b^2+24b^2-40b^2=0

We add all the numbers together, and all the variables

-8b^2=0

a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-16}=0$

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