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16d^2+40d+25=9
We move all terms to the left:
16d^2+40d+25-(9)=0
We add all the numbers together, and all the variables
16d^2+40d+16=0
a = 16; b = 40; c = +16;
Δ = b2-4ac
Δ = 402-4·16·16
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-24}{2*16}=\frac{-64}{32} =-2 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+24}{2*16}=\frac{-16}{32} =-1/2 $
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