16g(g+12)=528

Solution for 16g(g+12)=528 equation:

16g(g+12)=528

We move all terms to the left:

16g(g+12)-(528)=0

We multiply parentheses

16g^2+192g-528=0

a = 16; b = 192; c = -528;
Δ = b2-4ac
Δ = 1922-4·16·(-528)
Δ = 70656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{70656}=\sqrt{1024*69}=\sqrt{1024}*\sqrt{69}=32\sqrt{69}$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(192)-32\sqrt{69}}{2*16}=\frac{-192-32\sqrt{69}}{32}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(192)+32\sqrt{69}}{2*16}=\frac{-192+32\sqrt{69}}{32}
$