16m+5+4m=3(2-m)+19

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Solution for 16m+5+4m=3(2-m)+19 equation: 



16m+5+4m=3(2-m)+19

We move all terms to the left:

16m+5+4m-(3(2-m)+19)=0

We add all the numbers together, and all the variables

16m+4m-(3(-1m+2)+19)+5=0

We add all the numbers together, and all the variables

20m-(3(-1m+2)+19)+5=0



We calculate terms in parentheses: -(3(-1m+2)+19), so:

3(-1m+2)+19

We multiply parentheses

-3m+6+19

We add all the numbers together, and all the variables

-3m+25

Back to the equation:

-(-3m+25)



We get rid of parentheses

20m+3m-25+5=0

We add all the numbers together, and all the variables

23m-20=0

We move all terms containing m to the left, all other terms to the right

23m=20

m=20/23

m=20/23

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