16m2-98=0

Solution for 16m2-98=0 equation:

16m^2-98=0

a = 16; b = 0; c = -98;
Δ = b2-4ac
Δ = 02-4·16·(-98)
Δ = 6272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6272}=\sqrt{3136*2}=\sqrt{3136}*\sqrt{2}=56\sqrt{2}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56\sqrt{2}}{2*16}=\frac{0-56\sqrt{2}}{32}
=-\frac{56\sqrt{2}}{32}
=-\frac{7\sqrt{2}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56\sqrt{2}}{2*16}=\frac{0+56\sqrt{2}}{32}
=\frac{56\sqrt{2}}{32}
=\frac{7\sqrt{2}}{4}
$