If it's not what You are looking for type in the equation solver your own equation and let us solve it.
16n^2-9=0
a = 16; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·16·(-9)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*16}=\frac{-24}{32} =-3/4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*16}=\frac{24}{32} =3/4 $
| x+2x+40+x-20=180 | | 0.50x+4=0.25x+8 | | 3x-(-2x+10)=25 | | 2/5x+2x-8=26 | | 39+v=-31.666666 | | 0.50x+4=0.25+8 | | 6-(-3h)=18 | | 4y+15=6y-4y | | 4-2x=-3-3 | | 0=w/4+(-4) | | 2x+200=18- | | 2x-9=x+31 | | -2n=-11 | | n-(-11.3)=0.9 | | -2y+1=1-5 | | 5=(-y)+(-3) | | (2x+29)=135 | | 19x+2=21 | | 14+10u=13u−19 | | -10x+17-17x-1=32x+1 | | 4=3.1=y | | 6x+13=4x | | 6x+7=20=2x | | 10(11n+5)=-10-1090n | | 3^(-1x+1)-3^x=2 | | -2(x+2)=-4-2 | | 11+4c=5c+16 | | 18=-10.4+z/3 | | z/11=-13 | | 1/2(4y+18)+2=y | | -6x+6=3x-6 | | 52(x-8)=32(4x-25) |