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16p-3p=2/3p+5
We move all terms to the left:
16p-3p-(2/3p+5)=0
Domain of the equation: 3p+5)!=0We add all the numbers together, and all the variables
p∈R
13p-(2/3p+5)=0
We get rid of parentheses
13p-2/3p-5=0
We multiply all the terms by the denominator
13p*3p-5*3p-2=0
Wy multiply elements
39p^2-15p-2=0
a = 39; b = -15; c = -2;
Δ = b2-4ac
Δ = -152-4·39·(-2)
Δ = 537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{537}}{2*39}=\frac{15-\sqrt{537}}{78} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{537}}{2*39}=\frac{15+\sqrt{537}}{78} $
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