16p2+3p=0

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Solution for 16p2+3p=0 equation:



16p^2+3p=0
a = 16; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·16·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*16}=\frac{-6}{32} =-3/16 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*16}=\frac{0}{32} =0 $

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