16p2-24p+9=0

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Solution for 16p2-24p+9=0 equation: 



16p^2-24p+9=0

a = 16; b = -24; c = +9;
Δ = b2-4ac
Δ = -242-4·16·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{24}{32}=3/4$

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