16q=7+2(-8q+-3)

Solution for 16q=7+2(-8q+-3) equation:

16q=7+2(-8q+-3)

We move all terms to the left:

16q-(7+2(-8q+-3))=0

We add all the numbers together, and all the variables

16q-(7+2(-8q-3))=0


We calculate terms in parentheses: -(7+2(-8q-3)), so:

7+2(-8q-3)

determiningTheFunctionDomain
2(-8q-3)+7

We multiply parentheses

-16q-6+7

We add all the numbers together, and all the variables

-16q+1

Back to the equation:

-(-16q+1)


We get rid of parentheses

16q+16q-1=0

We add all the numbers together, and all the variables

32q-1=0

We move all terms containing q to the left, all other terms to the right

32q=1

q=1/32

q=1/32