16t-(8t+12)=1/3(12+24t)

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Solution for 16t-(8t+12)=1/3(12+24t) equation: 



16t-(8t+12)=1/3(12+24t)

We move all terms to the left:

16t-(8t+12)-(1/3(12+24t))=0



Domain of the equation: 3(12+24t))!=0

t∈R



We add all the numbers together, and all the variables

16t-(8t+12)-(1/3(24t+12))=0

We get rid of parentheses

16t-8t-(1/3(24t+12))-12=0

We multiply all the terms by the denominator


16t*3(24t+12))-8t*3(24t+12))-(1-12*3(24t+12))=0

We add all the numbers together, and all the variables

16t*3(24t+12))-8t*3(24t+12))-(1-12*3(24t=0

Wy multiply elements

144t^3(2+12))-(1-12*3(24t=0

We do not support etpression: t^3(2

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