16t-t2=60

Solution for 16t-t2=60 equation:

16t-t2=60

We move all terms to the left:

16t-t2-(60)=0

We add all the numbers together, and all the variables

-1t^2+16t-60=0

a = -1; b = 16; c = -60;
Δ = b2-4ac
Δ = 162-4·(-1)·(-60)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*-1}=\frac{-20}{-2}
=+10
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*-1}=\frac{-12}{-2}
=+6
$